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Results for Kiely, Julia Results for Kiely, Julia (Didcot)

Results for Kiely, Julia (Didcot)

ECF Grading Information

Current Standard Grading
Current Rapid Grading
Grading code 303804L
Current (2019) ECF Member Number inactive for this club   

From competitions in play from September 2009 onwards, opponents' gradings are fetched automatically from the ECF site. A missing grading implies that the player lists do not contain a valid Grade Code for that person, or that the present grade is blank. From 2011-12, grades are published in both July and January; both grades are listed.

Note: Cup results (if any) follow the oldest league results.

League results

2016-17 ODCL Division 1

Standard Gradings 35, 46
date for board against result
27 Feb 2017 Didcot 1 (A) 6 Weston, Richard 153 Cowley 1 0
0 out of 1 (excluding defaults) = 0%

2016-17 ODCL Division 4

Standard Gradings 35, 46
date for board against result
10 Oct 2016 Didcot 4 (H) 5 Chick, Robert 78 Cowley 5 1
01 Nov 2016 Didcot 4 (A) 6 Stubberfield, Derek 8 Wantage 2 1
08 Nov 2016 Didcot 4 (H) 6 Sterrie, David 74 Cumnor 2 0
14 Nov 2016 Didcot 4 (A) 6 Miller, David H 55 Cowley Workers 2 0
28 Nov 2016 Didcot 4 (A) 6 Bartle, John 72 Witney 4 0.5
16 Jan 2017 Didcot 4 (H) 6 Cassar, Etienne Bicester 2 0
26 Jan 2017 Didcot 4 (A) 6 Young, Imogen 42 Cowley 5 1
09 Mar 2017 Didcot 4 (A) 6 Steel, Robert 79 Cumnor 2 0
3.5 out of 8 (excluding defaults) = 43.75%

2015-16 ODCL Division 4

Standard Gradings ,
date for board against result
06 Oct 2015 Didcot 3 (A) 6 Howells, Paul Bicester 2 0
10 Nov 2015 Didcot 3 (A) 6 Spence, John 23 St Clare's 1
28 Jan 2016 Didcot 3 (A) 6 Dalziel, Liam 56 Cowley 5 0
25 Feb 2016 Didcot 3 (A) 6 Sterrie, David 74 Cumnor 2 0
21 Mar 2016 Didcot 3 (A) 6 Miller, David H 59 CWorkers 2 1
26 Apr 2016 Didcot 3 (A) 6 Kachkanov, Slava 30 Wantage 2 0
2 out of 6 (excluding defaults) = 33.33%

Cup results

 

2016-17 Frank Wood Shield

Standard Gradings 35, 46
date for board against result
10 Jan 2017 Didcot 4 (A) 6 Richards, Simon A 120 Wantage 1 0
0 out of 1 (excluding defaults) = 0%