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Results for Koehler, Benedikt Results for Koehler, Benedikt (Pimlico)

Results for Koehler, Benedikt (Pimlico)

ECF Rating Information

Current Standard Rating
Current Rapid Rating
Rating code 366806L
Current (2024) ECF Member Number   

From 2011-12 to 2019-20, grades were published in both July and January; both grades are listed. From 2020 onwards three-digit 'grades' were replaced by four-digit 'ratings'.

Opponents' ratings are fetched automatically from the ECF site. A missing rating implies that the a player's Rating Code has not been input by the team captain, or that the present rating is blank.

Note: Cup results (if any) follow the oldest league results.

League results

2024-25 Central London League Division 4

Standard rating initial, final
date for board against result
12 Dec 2024 Pimlico 4 (H) 3 Ewart, Thomas 1565A Hammersmith 3 0
13 Feb 2025 Pimlico 4 (A) 3 Mazzaracchio, Gianmaria 1603A Hammersmith 3 0
08 May 2025 Pimlico 4 (A) 3 Tierney, John 1253K Kings Head 2 0.5
0.5 out of 3 (excluding defaults) = 16.67%

LPSCL Division 1: 2024-25

Standard rating initial, final
date for board against result
20 Feb 2025 Pimlico Home (A) 5 Farnad, Safiullah 1705K Railsport 1 0
0 out of 1 (excluding defaults) = 0%

LPSCL Division 3: 2024-25

Standard rating initial, final
date for board against result
10 Oct 2024 Pimlico 4 (H) 4 Silvester, Paul 1421P Treasury 2 1
11 Nov 2024 Pimlico 4 (A) 4 Hobro, Gabriel 1342P DHSS 3 1
17 Jan 2025 Pimlico 4 (H) 5 Mattison, Richard 1205K DHSS 3 0
2 out of 3 (excluding defaults) = 66.67%

LPSCL Division 2: 2023-24

Standard rating initial, final
date for board against result
16 May 2024 Pimlico 3 (H) 5 Broad Michael 1615K Railsport 2 0
0 out of 1 (excluding defaults) = 0%

Cup results

 

Post Annual Cup 2024-25

Standard rating initial, final
date for board against result
30 Jan 2025 Pimlico3 (H) 5 Silvester, Paul 1341 Treasury2 1
30 Jan 2025 Pimlico3 (H) 5 Silvester, Paul 1341 Treasury2 1
30 Jan 2025 Pimlico3 (H) 5 Silvester, Paul 1341 Treasury2 1
3 out of 3 (excluding defaults) = 100%